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发送端译码判别驱动的LDPC码自适应编码传输方案

吕亚平,  马啸,  王千帆

吕亚平, 马啸, 王千帆. 发送端译码判别驱动的LDPC码自适应编码传输方案[J]. 电子与信息学报. doi: 10.11999/JEIT260840
引用本文: 吕亚平, 马啸, 王千帆. 发送端译码判别驱动的LDPC码自适应编码传输方案[J]. 电子与信息学报. doi: 10.11999/JEIT260840
LV Yaping, MA Xiao, WANG Qianfan. Transmitter-Side Decoding-Decision Driven Adaptive LDPC-Coded Transmission[J]. Journal of Electronics & Information Technology. doi: 10.11999/JEIT260840
Citation: LV Yaping, MA Xiao, WANG Qianfan. Transmitter-Side Decoding-Decision Driven Adaptive LDPC-Coded Transmission[J]. Journal of Electronics & Information Technology. doi: 10.11999/JEIT260840

发送端译码判别驱动的LDPC码自适应编码传输方案

doi: 10.11999/JEIT260840 cstr: 32379.14.JEIT260840
基金项目: 国家重点研发计划资助(2021YFA1000500),国家自然科学基金资助项目(No.62201626, No.62471506)
详细信息
    作者简介:

    吕亚平:女,博士生,研究方向为信源信道编码及其在无线通信中的应用

    马啸:男,教授,博士生导师,主要研究方向为信息与编码理论、编码调制技术、无线通信、光通信等

    王千帆:男,博士,香港城市大学博士后,主要研究方向为信道编码及其在无线通信中的应用

    通讯作者:

    马啸, maxiao@mail.sysu.edu.cn

  • 中图分类号: TN911

Transmitter-Side Decoding-Decision Driven Adaptive LDPC-Coded Transmission

Funds: National Key R&D Program of China (2021YFA1000500), The National Natural Science Foundation of China (No.62201626, No.62471506)
  • 摘要: 本文提出了一种发送端译码判别驱动的低密度奇偶校验码(LDPC)自适应编码传输方案。不同于现有方法在得到压缩序列后直接进行后续传输,所提方案在发送端先对有偏信源数据进行压缩,并执行一次本地解压缩译码;随后根据译码结果选择传输方案。具体地,若解压缩译码成功则对压缩后数据进行信道编码保护并发送,若译码失败则直接对原始数据采用信道编码传输。针对所提传输方案,本文给出了相应的并行译码和阈值译码算法,其中,并行译码分别在压缩后信道编码和未压缩信道编码两种假设下执行置信传播译码,其需要执行两次LDPC信道译码;而阈值译码则根据接收软信息判别发送端采用的传输方案,从而仅需执行一次LDPC译码。为了分析所提方案的性能,本文提出了一种权重组合界,其本质是根据发送端解压缩译码成功概率,对压缩后信道编码方案和未压缩信道编码方案的误帧率(FER)进行加权组合。仿真结果表明,所提传输方案的FER低于未压缩信道编码方案,所得FER与权重组合界基本吻合,并接近精灵辅助界。
  • 图  1  所提传输方案的发送端示意图

    图  2  $ \theta =0.07 $时不同SNR下两种传输方案的平均LLR统计量分布

    图  3  不同$ \theta $下压缩后信道编码方案的选择概率

    图  4  不同$ \theta $下各传输方案及性能界的FER曲线

    1  发送端传输方案

     输入:信源序列$ \boldsymbol{u} $,信源先验信息
     输出:实际二进制发送序列$ {\boldsymbol{c}}_{\text{t}} $
     1. 调用$ {\mathcal{C}}_{S}\left[K,K-k\right] $编码器,得到压缩序列$ \boldsymbol{s} $;
     2. 将压缩序列$ \boldsymbol{s} $和信源先验信息作为输入,执行BP解压缩译码,得到序列$ {\hat{\boldsymbol{u}}}_{\text{T}} $;
     3. 若$ {\hat{\boldsymbol{u}}}_{\text{T}}=\boldsymbol{u} $:在序列$ \boldsymbol{s} $末尾补$ K-k $个0构造$ K $长序列$ \left(\boldsymbol{s},0\right) $,对序列$ \left(\boldsymbol{s},0\right) $进行$ \mathcal{C}\left[N,K\right] $编码,得到码字$ \boldsymbol{c} $;
     将码字$ \boldsymbol{c} $中与补零序列对应的位置替换为翻转重复序列$ \boldsymbol{r} $,得到$ {\boldsymbol{c}}_{\text{t}} $;
     4. 若$ {\hat{\boldsymbol{u}}}_{\text{T}}\ne\boldsymbol{u} $:对序列$ \boldsymbol{u} $进行$ \mathcal{C}\left[N,K\right] $编码,得到码字$ \boldsymbol{c} $,并令$ {\boldsymbol{c}}_{\text{t}}=\boldsymbol{c} $。
    下载: 导出CSV
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  • 修回日期:  2026-10-16
  • 录用日期:  2026-10-16
  • 网络出版日期:  2026-10-22

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